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Post by peasant on Nov 11, 2023 17:09:40 GMT
How? My best idea so far is to integrate a bottle of compressed gas into the guidance package that cools as it expands and steals the heat from the electronic components as it flows over them on its way out. Can you see any flaws with this method? Can you suggest a better design?
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Post by yehang79 on Nov 12, 2023 2:39:50 GMT
since the evaporation heat of liquid nitrogen is 5.56kj/mol, absorbing 2000kj of heat only requires 7g liquid nitrogen so yeah its possible
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Post by peasant on Nov 20, 2023 11:20:05 GMT
 Source: apps.dtic.mil/sti/pdfs/ADA174324.pdfAssuming all of the power generated is eventually converted to heat, to absorb 3500 J/s continuously for a 10min flight, would require about 7,35kg of liquid nitrogen (without taking into account the container). Edit: if the outer hull of the missile is used as a radiator, the surface at 80°C would theoretically radiate 880W/m^2. Assuming a 1m diameter of the missile's hull and the width of radiating zone of 1m, gives surface area of 3,14m^2 which could, ideally, dissipate at most, 2764W of heat, or 78% of 3,5kW figure we took from that document. |
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Post by sage on Dec 9, 2023 3:03:47 GMT
Source: apps.dtic.mil/sti/pdfs/ADA174324.pdfAssuming all of the power generated is eventually converted to heat, to absorb 3500 J/s continuously for a 10min flight, would require about 7,35kg of liquid nitrogen (without taking into account the container). Edit: if the outer hull of the missile is used as a radiator, the surface at 80°C would theoretically radiate 880W/m^2. Assuming a 1m diameter of the missile's hull and the width of radiating zone of 1m, gives surface area of 3,14m^2 which could, ideally, dissipate at most, 2764W of heat, or 78% of 3,5kW figure we took from that document. Thank you for including a pdf link. You don't know how many people forget to do that here. Also is it 3.14m^2 or 3,140m^2? |
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Post by peasant on Dec 10, 2023 11:44:31 GMT
It's the former.
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