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Post by Enderminion on Apr 6, 2017 13:41:16 GMT
works, And i found out what happens when you delete a dependency before the parent, the launcher in question defaulted to the top of the list
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Post by The Astronomer on Apr 28, 2017 4:14:07 GMT
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Post by L5Resident on Apr 28, 2017 21:52:37 GMT
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Post by The Astronomer on Apr 29, 2017 4:14:09 GMT
I think it was discussed before, but there are some problems... Mainly, we don't know the properties of this metallic hydrogen yet.
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Post by The Astronomer on Apr 30, 2017 5:43:59 GMT
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Post by samchiu2000 on Apr 30, 2017 16:57:47 GMT
BTW i am still hoping nerd1000 to make the 90% HEU NSWR, although it is not very likely. But it's up to him and we have no right to push him, and i also try to do it myself and then back with a bunch of mysterious equations... |
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Post by The Astronomer on May 5, 2017 13:11:16 GMT
Note: The famous Deuterium + Helium-3 fusion is also an aneutronic fusion. This would be an awesome thing to mod in. nerd1000  |
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Post by nerd1000 on May 5, 2017 13:28:17 GMT
BTW i am still hoping nerd1000 to make the 90% HEU NSWR, although it is not very likely. But it's up to him and we have no right to push him, and i also try to do it myself and then back with a bunch of mysterious equations... Your wish is granted! I present the 90% HEU NSWR, assuming a fission rate of 10%. This gives around 45 times the energy density of the normal NSWR, allowing exhaust velocities of over 400 km/s. Material Super Zubrol
Elements H O U-235 U-238 Br
ElementCount 2 1 0.018 0.02 0.08
Density_kg__m3 1100
EnthalpyOfFormation_kJ__mol 4581765
BondDissociationEnergy_kJ__mol 927.01
GibbsFreeEnergyOfFormation_kJ__mol -237.14
BulkModulus_GPa 2.151
MeltingPoint_K 273
BoilingPoint_K 373
ThermalConductivity_W__m_K .609
SpecificHeat_J__kg_K 1180.6
Viscosity_Pa_s 1.0016e-3
Resistivity_Ohm_m 1.8e5
DielectricStrength_MV__m 65
RelativePermittivity 80.1
RelativePermeability .999992
RefractiveIndex Water
Material Depleted Super Zubrol
Elements H O U-235 U-238 Br Kr Ba
ElementCount 2 1 0.0162 0.02 0.08 0.0018 0.0018
Density_kg__m3 1100
EnthalpyOfFormation_kJ__mol -285.83
BondDissociationEnergy_kJ__mol 927.01
GibbsFreeEnergyOfFormation_kJ__mol -237.14
BulkModulus_GPa 2.151
MeltingPoint_K 273
BoilingPoint_K 373
ThermalConductivity_W__m_K .609
SpecificHeat_J__kg_K 1180.6
Viscosity_Pa_s 1.0016e-3
Resistivity_Ohm_m 1.8e5
DielectricStrength_MV__m 65
RelativePermittivity 80.1
RelativePermeability .999992
RefractiveIndex Water
ChemicalReaction 90%HEU Zubrin NSWR
Reactants Super Zubrol
ReactantCounts 1
Products Depleted Super Zubrol
ProductCounts 1
ActivationEnergy_kJ__mol 0.01
AutoignitionTemperature_K 273
CharacteristicLength_m 0.65
I also revised the specific heat capacity of the Zubrol to better reflect its composition. This value is an estimate based on the specific heat of Uranium Tetrafluoride, which was the closest thing I could find to UBr 4 with a readily available value for specific heat capacity. Any users of normal Zubrol should substitute this value into their current code: It makes the nozzle efficiency much higher, which allows you to match or exceed the performance levels predicted on Atomic Rockets within the game's limits for nozzle expansion ratio (in fact you can achieve 66 km/s with a short pusher plate like nozzle, which is what Dr Zubrin proposed in his original concept). |
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Post by The Astronomer on May 5, 2017 13:34:04 GMT
My wish is not granted ;-;
Btw, i need to put all of those formula in my excel... I think it's me being stupid with the numbers.
Is the formula eV x 1.602176565e-19 (eV -> J) x Avogadro's number?
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Post by samchiu2000 on May 5, 2017 13:35:19 GMT
BTW i am still hoping nerd1000 to make the 90% HEU NSWR, although it is not very likely. But it's up to him and we have no right to push him, and i also try to do it myself and then back with a bunch of mysterious equations... Your wish is granted! I present the 90% HEU NSWR, assuming a fission rate of 10%. This gives around 45 times the energy density of the normal NSWR, allowing exhaust velocities of over 400 km/s.
I also revised the specific heat capacity of the Zubrol to better reflect its composition. This value is an estimate based on the specific heat of Uranium Tetrafluoride, which was the closest thing I could find to UBr 4 with a readily available value for specific heat capacity. Any users of normal Zubrol should substitute this value into their current code: It makes the nozzle efficiency much higher, which allows you to match or exceed the performance levels predicted on Atomic Rockets within the game's limits for nozzle expansion ratio (in fact you can achieve 66 km/s with a short pusher plate like nozzle, which is what Dr Zubrin proposed in his original concept). You used "kids" to describe me (not totally wrong  ) and now i am like a kid in the candy shop  although these candy are radioactive  ...... But BTW don't Zurbin assumed a fission rate of 90% (Already it may NOT be REALISTIC...) And i looked into it and i think that we may need to figure out the characteristic length of the reaction...(Sorry for pointing it out...) |
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Post by samchiu2000 on May 5, 2017 13:36:49 GMT
My wish is not granted ;-; Btw, i need to put all of those formula in my excel... I think it's me being stupid with the numbers. Is the formula eV x 1.602176565e-19 (eV -> J) x Avogadro's number? Mysterious equation... |
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Post by nerd1000 on May 5, 2017 13:38:37 GMT
My wish is not granted ;-; Btw, i need to put all of those formula in my excel... I think it's me being stupid with the numbers. Is the formula eV x 1.602176565e-19 (eV -> J) x Avogadro's number? yes, that should give you the energy per mole of fuel reacted. Convert J to kJ and you're good to go. Make sure to only count energy that's supplied to charged particles. |
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Post by The Astronomer on May 5, 2017 13:39:39 GMT
My wish is not granted ;-; Btw, i need to put all of those formula in my excel... I think it's me being stupid with the numbers. Is the formula eV x 1.602176565e-19 (eV -> J) x Avogadro's number? yes, that should give you the energy per mole of fuel reacted. Convert J to kJ and you're good to go. Make sure to only count energy that's supplied to charged particles.Huh? How? :/ |
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Post by nerd1000 on May 5, 2017 13:45:06 GMT
My wish is not granted ;-; Btw, i need to put all of those formula in my excel... I think it's me being stupid with the numbers. Is the formula eV x 1.602176565e-19 (eV -> J) x Avogadro's number? Mysterious equation... It's actually pretty simple. The energy of a nuclear reaction is usually given in electronvolts, eV. The 1.602x10^-19 converts electron volts to joules, which is the unit of energy we're interested in for the in-game configs. This is only the energy for one reaction event though (a single atom fuses with another). Avogadro's number is the number of carbon atoms in 12 grams of carbon-12. If we multiply the energy per reaction event by Avogadro's number we get the energy per mole of reactant fused, which we can then divide by 1000 (converting from J/mol to kJ/mol) and use as the value for the enthalpy of formation of the fusion fuel. |
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Post by samchiu2000 on May 5, 2017 13:46:59 GMT
It's actually pretty simple. The energy of a nuclear reaction is usually given in electronvolts, eV. The 1.602x10^-19 converts electron volts to joules, which is the unit of energy we're interested in for the in-game configs. This is only the energy for one reaction event though (a single atom fuses with another). Avogadro's number is the number of carbon atoms in 12 grams of carbon-12. If we multiply the energy per reaction event by Avogadro's number we get the energy per mole of reactant fused, which we can then divide by 1000 (converting from J/mol to kJ/mol) and use as the value for the enthalpy of formation of the fusion fuel. I just CAN'T believe you DON'T know about NUCLEAR physic... |
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) and now i am like a kid in the candy shop 
although these candy are radioactive 
...... But BTW don't Zurbin assumed a fission rate of 90% (Already it may NOT be REALISTIC...) And i looked into it and i think that we may need to figure out the characteristic length of the reaction...(Sorry for pointing it out...)