|
|
Post by nerd1000 on May 6, 2017 6:31:29 GMT
Are the numbers in Activation energy and Enthalpy of formation the one you got from the electronvolts -> Joules per mole equation? If so you should only have that number once, on either 'rocket deuterium' or 'rocket He3'. Otherwise you'll get double the energy you should have. Should I half the number of both down? Should work. Edit: also, you should correct your tutorial on the first page. |
|
|
|
Post by The Astronomer on May 6, 2017 6:35:50 GMT
Should I half the number of both down? Should work. Edit: also, you should correct your tutorial on the first page. Uh, I don't see anything wrong there? :/ |
|
|
|
Post by nerd1000 on May 6, 2017 6:58:36 GMT
Should work. Edit: also, you should correct your tutorial on the first page. Uh, I don't see anything wrong there? :/ You've put down the calculation for heat of formation as the calculation for activation energy. |
|
|
|
Post by The Astronomer on May 6, 2017 7:11:42 GMT
Uh, I don't see anything wrong there? :/ You've put down the calculation for heat of formation as the calculation for activation energy. It's a calculation for activation energy for ActivationEnergy_kJ__mol ._. |
|
|
|
Post by nerd1000 on May 6, 2017 10:26:58 GMT
You've put down the calculation for heat of formation as the calculation for activation energy. It's a calculation for activation energy for ActivationEnergy_kJ__mol ._. I explained it poorly. Look here: en.wikipedia.org/wiki/Activation_energy. The activation energy doesn't have much to do with the energy released by the reaction (activation energy for p-B11 should be much higher than for D-He3, even though the p-B11 reaction energy is lower). When we take the fusion energy in eV and convert it to in-game units we're working out the energy difference between reagents and products. The activation energy is the height of the barrier between those two states that must be surmounted for the reaction to take place. Normally this is achieved by heating the reagents until the molecules/atoms have enough kinetic energy to get over the barrier when they collide with other reagent molecules. This is true for both chemical reactions and nuclear ones- in a chemical reaction the activation energy is the energy needed to break the bonds in the reagents so that the reaction can take place, while in a nuclear fusion reaction the activation energy is the energy needed for the two nuclei to push through each other's electrostatic repulsion and collide. So the energy released by the reaction is independent of the activation energy. The game wants both, presumably because the activation energy can be used to calculate reaction rate (which is probably relevant for working out detonation velocities). |
|
|
|
Post by samchiu2000 on May 6, 2017 12:20:28 GMT
Actually can anyone tell me he critical mass of the nuclear salt water used in NSWR? Because i want to make my designs more realistic  |
|
|
|
Post by bigbombr on May 6, 2017 14:27:43 GMT
The NSWR makes for great 'kinetic' missiles (if the enemy shoots them, they detonate like a nuke, often ripping nearby enemies to shreds.
|
|
|
|
Post by Enderminion on May 6, 2017 18:06:44 GMT
Actually can anyone tell me he critical mass of the nuclear salt water used in NSWR? Because i want to make my designs more realistic U-235 has a critical mass of 52kg, U-233 sits at 15 kilograms, although its suspended in water, in Boron tanks so it can't form critical mass letmegooglethat.com/?q=Critical+Mass |
|
|
|
Post by samchiu2000 on May 7, 2017 0:05:51 GMT
Actually can anyone tell me he critical mass of the nuclear salt water used in NSWR? Because i want to make my designs more realistic U-235 has a critical mass of 52kg, U-233 sits at 15 kilograms, although its suspended in water, in Boron tanks so it can't form critical mass letmegooglethat.com/?q=Critical+MassBut how can we calculate the critical mass when we are using compound with fissile material instead of pure fissile? BTW the project rho said that the 20%EU nuclear salt water have a critical mass of about 50kg, and I am really doubtful about it since 50kg of 20%EU NSW only have about 427g of 20% enriched U235 in it... |
|
|
|
Post by Enderminion on May 7, 2017 1:03:01 GMT
But how can we calculate the critical mass when we are using compound with fissile material instead of pure fissile? BTW the project rho said that the 20%EU nuclear salt water have a critical mass of about 50kg, and I am really doubtful about it since 50kg of 20%EU NSW only have about 427g of 20% enriched U235 in it... if 20% of the tanks carrieage is U-233 Salt, and that is 20% enriched then you calculate the critical mass of the salts without the water, which is not something I have off the top of my head so, letmegooglethat.com/?q=Calculating+Critcal+Mass second link is a pdf |
|
|
|
Post by samchiu2000 on May 7, 2017 2:32:48 GMT
But how can we calculate the critical mass when we are using compound with fissile material instead of pure fissile? BTW the project rho said that the 20%EU nuclear salt water have a critical mass of about 50kg, and I am really doubtful about it since 50kg of 20%EU NSW only have about 427g of 20% enriched U235 in it... if 20% of the tanks carrieage is U-233 Salt, and that is 20% enriched then you calculate the critical mass of the salts without the water, which is not something I have off the top of my head so, letmegooglethat.com/?q=Calculating+Critcal+Mass second link is a pdf Sorry but I just can't understand these equations... |
|
|
|
Post by The Astronomer on May 7, 2017 2:33:34 GMT
I've edited the Deuterium + Helium-3 Fusion reaction and added element proton to mock the real one. Note that their properties are copied from hydrogen except their molar mass, which is just slightly lower than hydrogen. Use it to replace hydrogen, then rebalance the reaction.
|
|
|
|
Post by RiftandRend on Jun 4, 2017 4:28:21 GMT
Found a graph showing p+ 11B fusion activation energies. p+ 11B Fusion seems to have 2 cross sectional peaks, one at ~145 KeV and one at ~550 KeV We don't have any way to punish low cross sections with our current model, So an average of the 2 should be selected. iec.neep.wisc.edu/images/crossSections.jpg |
|
|
|
Post by RiftandRend on Jun 4, 2017 5:11:08 GMT
Also, the autoignition temperatures should be changed to match the kelvin equivalents of the KeV cross sectional peaks.
|
|
|
|
Post by The Astronomer on Jun 4, 2017 11:07:08 GMT
Do radiation (gamma ray) count in the reaction's energy output?
|
|
